![]() ![]() In this article, we saw the concept of Matlab find the index. If that number is not present in that row, then it returns an empty. ![]() Now we find a specific value for that we use a = operator, so we write command as find(Y=1.6) then it displays the index value where 1.6 is present. So in this example, we take a number in the range of 1 to 3 with the difference of 0.3, and these elements take into a variable ‘Y’ the numbers are 1.3, 1.6, 1.9, 2.2, 2.5, and 28. Let us see an example for find function, as we know to find function used to find indices and values of nonzero value. Then now, we use a find function, find(Y<15,10) it is used to find the first 10 elements that are less than 15 in a 5 by 5 magic square matrix, and the indices values of that 10 numbers are stored in D variable and display it. So in our example, we take magic(5) which means it creates a 5 by 5 matrix the numbers are 1 to 25 because 5^2. In this example, we take a 5 by 5 matrix using a magic function magic creates a matrix if we take magic(n), it creates a by n matrix the matrix number is 1 to n^2 with equal rows and columns. The result of D and D2 shows in n*1 format, where n is the number of rows. So now we use a find function we take to find(Y) this command displays the indices of nonzero values like in our examples non zero values are 1, 2, 5, 7 and 4 the find displays the indices values of these numbers, and then we take a complement of 1st command that is found (~Y), this command is used to display the indices value of zero values present in the matrix so that indices are stored in d2 variable.Īs we saw the result, the Y variable shows the 3 by 3 matrix, then the D stores the indices values of nonzero values present at the Y matrix and the D2 stores the value of indices of a zero present in the matrix. So index 1 starts with row 1 and column one, and the next index value is 2 corresponds to row 2 and column one, then the same sequence will continue till the last index value in our example, the last index value is 9 because we take 3-by-3 matrix. So in this example, we take a 3-by-3 matrix, and this matrix takes into a variable ‘Y’. Let us see an example related to find function, find function used to find indices and values of nonzero value. Given below are the examples of Matlab find Index: Example #1 Step 2: Then, we use a find statement with proper syntax to find indices and values of the nonzero element. Step 1: We need to take all elements into a variable ![]() The steps to find indices and values of nonzero value using find the statement:. For finding indices and values of nonzero elements, we need to take all elements into a variable and use proper syntax. I also really don't think this is the best strategy, since the max chain in my data will be tens of thousands of values.Find the function used to find indices and values of nonzero value. I am sure this is a relatively simple thing to do so I was hoping someone could offer insight.ĮDIT: Here's what I tried: s = zeros(size(x1)) įor a vector x1 which has a max chain of 72 but I dont know how to find the max chain and return its first value, so I know where to trim. I need to get rid of these rows before I can start analyzing the movement from the trials. I am working with movement data from a joystick and there are a few thousand rows of data with a mix of zeros and nonzero values before the actual trial begins (coming from subjects slightly moving the joystick before the trial actually started). I am trying to write a simple MATLAB program that will find the first chain (more than 70) of consecutive nonzero values and return the starting value of that consecutive chain. ![]()
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